Soal:
Untuk
bilangan real positip x, jika x – 12 = 1/x maka nilai dari x4 – 10x3 –15x2
–122x + 2012 = ...
Pembahasan:
Diketahui: x – 12 =
1/x
x – 12 =
1/x ==> x2
– 12x = 1 (dikalikan x)
==> x2 = 12x + 1
==> x3 = 12x2 + x
==> x3 = 12(12x + 1) + x
==> x3 = 144x + 12 + x
==> x3 = 145x + 12
x – 12 = 1/x ==> x4 – 12x3 = x2 (dikalikan x3)
==> x4 = 12(145x + 12) + (12x + 1)
==> x4 = 1740x + 144 + 12x + 1
==> x4 = 1752x + 145
Dengan demikian:
x4 – 10x3 –15x2 – 122x + 2012 = 1752x + 145
– 10(145x + 12) – 15(12x
+ 1) – 122x + 2012
=
1752x + 145 – 1450x – 120 – 180x – 15 – 122x + 2012
=
1752x – 1752x + 10 + 2012
=
2022
Jadi, nilai dari x4 – 10x3 –15x2
–122x + 2012 = 2022
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Pelajari Juga: [Nomor 1], [Nomor 2], [Nomor 3], [Nomor 4], [Nomor 5], [Nomor 6],
[Nomor 8], [Nomor 9], [Nomor 10], dan [Nomor 11 - 20]
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